5x^2-7x+15=0

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Solution for 5x^2-7x+15=0 equation:


Simplifying
5x2 + -7x + 15 = 0

Reorder the terms:
15 + -7x + 5x2 = 0

Solving
15 + -7x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
3 + -1.4x + x2 = 0

Move the constant term to the right:

Add '-3' to each side of the equation.
3 + -1.4x + -3 + x2 = 0 + -3

Reorder the terms:
3 + -3 + -1.4x + x2 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1.4x + x2 = 0 + -3
-1.4x + x2 = 0 + -3

Combine like terms: 0 + -3 = -3
-1.4x + x2 = -3

The x term is -1.4x.  Take half its coefficient (-0.7).
Square it (0.49) and add it to both sides.

Add '0.49' to each side of the equation.
-1.4x + 0.49 + x2 = -3 + 0.49

Reorder the terms:
0.49 + -1.4x + x2 = -3 + 0.49

Combine like terms: -3 + 0.49 = -2.51
0.49 + -1.4x + x2 = -2.51

Factor a perfect square on the left side:
(x + -0.7)(x + -0.7) = -2.51

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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